Escaping \1 \11 without my mind escaping me

[Laurent Chouinard]

Basically, this string constant is declared in rom:
byte const foobar[10] = {"\1hi there!"};

1st character is binary value 1, because i use the escape sequence to get it in. That's what i want.

Now i need to add the digit 1 after it in the string, or hex value 31

If I do this:
byte const foobar[10] = {"\11hi there"};
I'm doomed! Ascii value 11 goes there instead.

So basically I could do this:
byte const foobar[10] = {"\1\x31hi there"};
But that sure is ugly. Especially to the person who's going to read that and make sense of it when translating or something.

Any ways to stop the escaping to stop escaping? Or maybe i'm just not seeing clear today.

[PCM programmer]

Use the full 3 digits of the octal sequence (i.e., \001). Then it works.
Example: