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thanhhavdt
Joined: 09 Oct 2006
Posts: 12
Location: hoangsam
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| Help me 16 bit decimal convert to BCD code |
 Posted: Sat Apr 13, 2024 10:46 am |
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Why not return BCD value in my program?
| Code: |
#include <16f887.h>
#device *=16
#device adc=10
#fuses nowdt,xt,noput,protect,nodebug,nobrownout,nolvp
#use delay(clock=4000000)
//#include <internal_eeprom.c>
//#bit ResetRom = 0x05.5 //RA5 (PIN 7)
#byte PORTA = 0x05
#byte PORTB = 0x06
#byte PORTC = 0x07
#byte PORTD = 0x08
#byte PORTE = 0x09
#byte TRISA = 0x85
#byte TRISB = 0x86
#byte TRISC = 0x87
#byte TRISD = 0x88
#byte TRISE = 0x89
#bit re0 = 0x09.0 // DS_PIN
#bit re1 = 0x09.1 //SHCP_PIN
#bit re2 = 0x09.2 //STCP_PIN
/* IC74HC595 */
#define SHCP_PIN PIN_E1
#define DS_PIN PIN_E0
#define STCP_PIN PIN_E2
byte Lo_Data_DKX ;
byte Hi_Data_DKX ;
int16 a=10;
int16 b=0;
int16 c=0;
int16 d=0;
int16 Data_DKX = 0;
int16 Data_CHIA = 0;
int16 Data = 0;
void convert_data_DKX()
{
Data_DKX = (((800*a)+(80*(b+25))+(8*c)+d));
Data_CHIA = (Data_DKX)/2;
Hi_Data_DKX = (unsigned char) ((((Data_CHIA / 1000) % 10) << 12) |(((Data_CHIA / 100) % 10) << 8) ) ;
Lo_Data_DKX = (unsigned char) ((((Data_CHIA / 10) % 10) << 4) | (Data_CHIA % 10));
}
void IC_74hc595(int data)
{
int i;
output_low(SHCP_PIN);
for(i=0;i<=7;i++)
{
if((data & 0x80)==0)
{output_low(DS_PIN);
delay_us(50);}
else
output_high(DS_PIN);
data=data<<1;
output_high(SHCP_PIN);
output_low(SHCP_PIN);
}
}
void IC_74HC595_Output()
{
output_low(STCP_PIN);
delay_ms(50);
output_high(STCP_PIN);
output_low(STCP_PIN);
}
void write_to_595 (byte Lo_Data_DKX, Hi_Data_DKX)
{
IC_74hc595(Hi_Data_DKX);
IC_74hc595(Lo_Data_DKX);
IC_74HC595_Output();
}
void send_data_DKX()
{
convert_data_DKX();
write_to_595(Lo_Data_DKX, Hi_Data_DKX);
}
void main(void)
{
TRISA=0x00; //PortA as OUTPUT, RA5 as INPUT
TRISB=0xFF; //PortB as INPUT
TRISC=0x00; //PortC as OUTPUT
TRISD=0xFF; //PortD as INPUT
TRISE=0x00; //PortE as OUTPUT
PORTC=0; //
PORTE=0;
while(true)
{
send_data_DKX();
}
} |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19495
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| Posted: Sun Apr 14, 2024 1:52 am |
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First thing. Document, document, document.
We have no idea of what you are actually trying to do, and you yourself,
if you come back to this code in a few years time, will also have no idea
what it is meant to do. Documentation is your friend, and gives a place
to start. It also will often make obvious what is going wrong.....
Now, I'll make some comments in your routine, and this may help you
get a key to the problem:
| Code: |
void convert_data_DKX()
{
//Much better really to pass variables to the function rather than
//using globals.
Data_DKX = (((800*a)+(80*(b+25))+(8*c)+d));
//Now what on earth is this meant to do?. You are passing it four
//int16 values 10, 0, 0, 0
//so 10*800 = 8000
//80*25 = 2000
//result will be 10000.
//Why the strange multiplication, and the addition of 25?????
Data_CHIA = (Data_DKX)/2;
//Why over 2?. Now 5000. At least this can fit into four BCD
//'digits'.
Hi_Data_DKX = (unsigned char) ((((Data_CHIA / 1000) % 10) << 12) |(((Data_CHIA / 100) % 10) << 8) ) ;
//Now this looks as if you are trying to code this is binary
//nibbles, not 'BCD' digits. So you possibly want:
// 0b0101 0000 (0x 50)
// 0b0000 0000 (0x 00)
//Big problem here is your cast. You are generating the nibble into the
//high byte of a 16bit value, then casting this to an unsigned char. At
//this point the high byte is _thrown away_. You get just the low byte
//result 00.........
//Given you want only the high byte here:
Hi_Data_DKX=(((Data_CHIA/1000) %10) <<4) + (Data_CHIA/100)%10;
//Now this gives the 'thousands' moved to the high nibble of the
//resulting byte, and the hundreds in the low nibble. Exactly what
//is needed.
//This is exactly what you code below, but doing the high two digits.
//The problem was you were generating '0x 5000', then taking the
//low byte of this result. Answer = 0, not 0x50.... :(
Lo_Data_DKX = (unsigned char) ((((Data_CHIA / 10) % 10) << 4) | (Data_CHIA % 10));
}
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thanhhavdt
Joined: 09 Oct 2006
Posts: 12
Location: hoangsam
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| Posted: Sun Apr 14, 2024 8:57 am |
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| Thanks Ttelmah!!! |
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