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No return from function, why?

 
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eabir



Joined: 16 Aug 2010
Posts: 19

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No return from function, why?
PostPosted: Wed Nov 16, 2011 10:01 am     Reply with quote

Hi,

Why do the Visual_on () function is endless and dont return to main after finish the 'for' loop ?

Code:

#include <10F222.h>
#device adc=8

#FUSES NOWDT                      //No Watch Dog Timer
#FUSES NOMCLR                     //Master Clear pin: disable
#FUSES NOPROTECT                  //Code protected from reads
#FUSES NOMCPU                      //No Watch Dog Timer
#FUSES IOSC4
#use delay(Clock=4MHZ,OSC)
 //      #use delay(clock=40)         // Only for Debug Mode
 //     #use delay(clock=1000000)         // Only for Debug Mode
#bit OSCCAL_0 = 0x05.0           // Disable OSC on GP2, Enable as I/O

//==============================//
// Configuration bits:
//   1.MCPU = Pull up disabled
//  2.WDT = disabled
//  3.MCLRE = I/O & tied to VDD
//========================================================================


  Sound_on (void)
   {

      int8 step = 0;
            
      for(step = 0;step < 1 ;step++ ){  // 
        //   cnt0 = 0;
         
          output_low(PIN_B1); // Play sound
        }
 }
 
  Visual_on (void)
   {
      int16 step = 0;   
      for(step = 0;step < 1 ;step++ ){  //  Loop control
           output_low(PIN_B2); // Sound sequence       
           delay_ms(100); //6Khz     was 73??     
     
          }
      return:
      }
     
 void main()
{
 
   int8 step;
   int8 temp_val;
   int8 val_ref_lo = 0;
   int8 val_ref_hi = 0;
   int8 Val = 0;
   int8 avalue;
   int8 value;   
   int8 cnt0 = 0; // counter
   OSCCAL_0 = 0;         //set bit 0 in reg 5 to zero.
   setup_adc_ports(sAN0);
   setup_adc(ADC_CLOCK_DIV_4);
   setup_adc( ADC_ON );
       
   setup_timer_0(RTCC_INTERNAL|RTCC_DIV_1);
   setup_counters(RTCC_INTERNAL,RTCC_DIV_1|DISABLE_PULLUPS); //|DISABLE_PULLUPS
   setup_wdt(WDT_2304MS);
     
  //   output_low(PIN_B2); 
      output_high(PIN_B2); 
 
set_adc_channel(0);
delay_ms( 20000 );       //wait
temp_val = read_adc(); // first reference adc read

while (1)  {

   
output_high(PIN_B1); // 
//output_low(PIN_B2); // 
output_high(PIN_B2); // 


 
         value = read_adc();

           delay_us(100);

            avalue = read_adc();

            delay_us(100);

             val_ref_lo = temp_val - 1; 
         val_ref_hi = temp_val + 1; 
         Val = value -avalue;      

       if (((avalue <= val_ref_lo) || (val_ref_hi <= avalue)) && (Val < 2))
         
         cnt0 = 1;

         delay_ms( 4000 );

         if (cnt0 == 1 && Val < 1)
       
// Activate  //   
    
        for(step = 0;step < 1 ;step++ ){
          delay_ms( 100);
       
           Visual_on (); //
                  Sound_on (); // 

         }
      
   
    else
   //   output_low(PIN_B2); //
       output_high(PIN_B2); //                        
 }
   
}
Geps



Joined: 05 Jul 2010
Posts: 129

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PostPosted: Wed Nov 16, 2011 10:03 am     Reply with quote

Semi colon _after_ the return help?
asmboy



Joined: 20 Nov 2007
Posts: 2128
Location: albany ny

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PostPosted: Wed Nov 16, 2011 8:32 pm     Reply with quote

How about you explain what YOU WANT visual_on and
sound_on to do --- and why any loop is required.

And then also mention HOW Many times you think
the loops are executed in each ??
eabir



Joined: 16 Aug 2010
Posts: 19

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PostPosted: Thu Nov 17, 2011 12:55 am     Reply with quote

I tried return(0), no help.

Even if there is no loop in the visual_on(), the function dont return to main.
FvM



Joined: 27 Aug 2008
Posts: 2337
Location: Germany

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PostPosted: Thu Nov 17, 2011 1:24 am     Reply with quote

Do you actually see it's not returning? How? Or is it only a conclusion?
eabir



Joined: 16 Aug 2010
Posts: 19

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HW problem
PostPosted: Thu Nov 17, 2011 2:43 am     Reply with quote

guys,

thank you all, but its a hardware problem of the I/O ports, (after checked with ICE)
temtronic



Joined: 01 Jul 2010
Posts: 9221
Location: Greensville,Ontario

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PostPosted: Thu Nov 17, 2011 6:09 am     Reply with quote

It'd be interesting to see the listing to see how the compiler codes.....

for(step = 0;step < 1 ;step++ )

...
RF_Developer



Joined: 07 Feb 2011
Posts: 839

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PostPosted: Thu Nov 17, 2011 6:29 am     Reply with quote

Probably it'd code it just like any other for loop on an int loop variable. I doubt the compiler/optimiser is clever enough to realise the inner loop code is 'Allo 'Allo code (i.e. will execute only once), and that the loop test/increment can be optimised away.

RF D.
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