How can I divide a 16 bit value into 8 bit values?

[theasus]

How can I divide a 16 bit value into 8 bit values?For example;
int16 value;
int8 LSB,MSB;
value=0x4F87;
And I want to change LSB and MSB's values as;
LSB=87;
MSB=4F;
How can I do this?

[RayJones]

My favorite method is to use a structure/union approach.

You can use the inbuilt macro functions to do it, but I simply like the elegance of reading or writing a value directly from/to where it is meant to live.

http://www.ccsinfo.com/forum/viewtopic.php?p=103397&highlight=#103397

Is my "old chestnut" as I like to refer to it :-)

Cheers, Ray

[theasus]

I couldn't get any result from your link. Could you write a sample about it?

[FvM]

Ray Jones found the said elegance in a union construct. If you have problem to read it from the link,
a C programming text book or the CCS C manual should help as well. Sooner or later, you won't be
able to ignore these sources, there's not always a forum to spoon feed basic programmers knowledge.

Besides the portable generic C constructs for type manipulation, you should also notice the CCS proprietary make8() function.

[theasus]

Sorry about that I understood what you mean I solved my problem.

int16 b;
int LSB,MSB;
LSB=make8(b,0);
MSB=make8(b,1);

Thanks for your considerations.

[RayJones]