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| convert integer to string |
 Posted: Wed Apr 30, 2008 9:24 pm |
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hi, Any one done any form to convert long integer 32 bits in formated string with 'n' zeros left ?
ccs have built in function sprint to do convert (ie)
char str[ 9 ] = "00000000"; //initial value of string 8 zeros
int32 x = 0x07D8 //initial value of integer 2008
sprintf(str, "%lu", x); //result "2008"
the result is correct in string str, but i wold like and need to result "000002008" with n zeros to left.
any one have idea to do is ??
best regards, Renato |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Wed Apr 30, 2008 10:15 pm |
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The test program shown below displays this output:
| Code: |
#include <18F452.h>
#fuses XT,NOWDT,NOPROTECT,BROWNOUT,PUT,NOLVP
#use delay(clock=4000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, ERRORS)
//====================================
void main()
{
char str[20];
int32 x = 2008;
sprintf(str, "%09lu", x);
printf(str);
while(1);
} |
This was tested with compiler vs. 4.071. |
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Democrito
Joined: 20 Aug 2010
Posts: 2
Location: Tibet
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| Posted: Fri Aug 20, 2010 5:59 pm |
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| I was looking for exactly this. Thank you so much! |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19499
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| Posted: Sat Aug 21, 2010 4:30 am |
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and of course, note carefully, that PCMprogrammer made the string longer, since your required output (9 characters), requires a minimum of _10_ characters of storage for the string.
Best Wishes |
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sumesh89
Joined: 17 Dec 2011
Posts: 2
Location: Kerala
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| Posted: Fri Dec 23, 2011 10:17 pm |
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Thanku 
_________________
the more i think the confused i get |
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