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George96
Joined: 29 Dec 2016
Posts: 2
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| INT_RDA and INT_RDA2 |
 Posted: Thu Dec 29, 2016 4:47 pm |
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Hola buen día , estoy realizando un pequeño proyecto en el cual tengo que utilizar las interrupciones de los dos puertos seriales que posee el PIC18F25K22. El código es el siguiente.
Hi, good morning, I'm doing a little project in which I have to use the interruptions of the two serial ports that the PIC18F25K22 has. The code is as follows.
| Code: | #include <18F25K22.h>
#device ADC=10
#use delay(internal=8MHz)
#priority INT_RDA,INT_RDA2
#use rs232(baud=9600,parity=N,xmit=PIN_C6,rcv=PIN_C7,bits=8,stream=PORT1)
#use rs232(baud=19200,parity=N,xmit=PIN_B6,rcv=PIN_B7,bits=8,stream=PORT2)
#INT_RDA
void RDA_isr(void)
{
fprintf(PORT1,"HOLA1");
}
#INT_RDA2
void RDA_isr2(void)
{
fprintf(PORT2,"HOLA2");
}
void main()
{
enable_interrupts(GLOBAL);
enable_interrupts(INT_RDA);
enable_interrupts(INT_RDA2);
while(TRUE)
{
//TODO: User Code
}
} |
Por lo cual si yo mando información por el primer puerto estaré reviviendo un hola1 y por el contrario si yo envió información por el segundo puerto estaré reviviendo hola2.
El problema empieza cuando yo le mando información por el primer o segundo puerto y al entrar a la interrupción esta se repite infinitamente sin algo que la detenga, en otras palabras , cuando yo le envio un carácter por cualquier puerto , infinitamente me devuelve hola1 o hola2.
No entiendo por que se queda metido en un ciclo la interrupción. Espero alguien me pueda orientar. Gracias
So if I send information on the first port I will be receiving a hello1 and on the other hand if I sent information on the second port I will be receiving hello2 .
The problem starts when I send information for the first or second port and when entering the interruption it repeats itself infinitely without something stopping it, in other words, when I send a character to it by any port, infinitely it returns hello1 or hello2 .
I do not understand why the interruption is in a cycle. I hope someone can guide me. Thank you.
Last edited by George96 on Thu Dec 29, 2016 5:57 pm; edited 1 time in total |
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George96
Joined: 29 Dec 2016
Posts: 2
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| Re: Interrupciones del Puerto Serial |
| Posted: Thu Dec 29, 2016 4:56 pm |
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| My compiler version is 5.061 |
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temtronic
Joined: 01 Jul 2010
Posts: 9221
Location: Greensville,Ontario
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| Posted: Thu Dec 29, 2016 8:06 pm |
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generally speaking...
When you send a character to the PIC UART you MUST read the UART buffer to clear the interrupt. If you don't ,then the PIC will enter the ISR, do what's there, then leave BUT as soon as it leaves the ISR it sees the Interrupt flag set so it goes to the ISR, do what's there, then leave....... it'l do this until you clear the interrupt flag, which is done by reading the UART buffer.
The other thing you MUST do is add 'errors' to the use RS232(...... options....) .The HW UART buffer is 2-3 characters so if YOU don't clear(read) them #4 will 'hang' the PIC.
Jay |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Thu Dec 29, 2016 8:09 pm |
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I see that Temtronic posted about the same time as me. I'll leave my
post up anyway.
-------------------
You have to actually read the received byte in the #int_rda or #int_rda2
routine with fgetc(). Example:
| Code: |
#INT_RDA
void RDA_isr(void)
{
int8 temp;
temp = fgetc(PORT1); // Get the char to clear interrupt
fprintf(PORT1,"HOLA1");
} |
Also, it's not normally a good idea to do lengthy procedures, such as
sending a string, while inside an interrupt routine. It's OK to do this
in a test program, where you press a key and you see a response
on the serial terminal. But a programmer does not normally do this
in a real program. |
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