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congbinhdbk
Joined: 27 Aug 2013
Posts: 1
Location: Việt Nam
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| Bit banging SPI |
 Posted: Tue Aug 27, 2013 9:18 pm |
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Hi all!
I'm working with SPI by Software. I'm coding for slave with PIC18F4620 and have a problems. I receive data from master is ok but i can't transmit data from slave to master. Please help me!
| Code: |
int spi_io_read(int data_out) {
int data_in=0;
signed int i;
sdo=0;
for(i=7;i>=0;i--) {
//set data to SDO
if(bit_test(data_out,i)==1) sdo=1;
else sdo=0;
//waiting for clock
cnt=0;
while((sck==0)&&(cnt<=100)) {
cnt++;
}
while((sck==1)&&(cnt<=200)) {
cnt++;
}
//read data in SDI
if(sdi==1) bit_set(data_in,i);
else bit_clear(data_in,i);
}
return data_in;
} |
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alan
Joined: 12 Nov 2012
Posts: 357
Location: South Africa
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| Posted: Tue Aug 27, 2013 11:04 pm |
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Your sample data on the opposite edge from writing data to the bus. This all depends on your setup. See http://en.wikipedia.org/wiki/Serial_Peripheral_Interface_Bus for full description.
You sample and write on the same edge.
Also much more efficient code to do it as below
| Code: |
for (i=0; i <8 ; i++) {
if (bit_test(data_out,7) sdo=1;
else sdo = 0;
data_out <<=1;
}
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Compiler can work out bit position at compile time instead of run time which involves more instructions.
Regards
Alan |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19498
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| Posted: Wed Aug 28, 2013 3:59 am |
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Given that both the input byte, and output byte will be handling the same 'bit' at a time, I'd say it'd be more efficient, to use a single mask. So something like:
| Code: |
int spi_io_read(int data_out) {
int8 data_in=0;
int8 mask=0x80; //MSb first
sdo=0;
do
{
//wait for the first falling edge
cnt=0;
while((sck==1)&&(cnt<=100)) {
cnt++;
}
//set data to SDO
if(data_out & mask) sdo=1;
else sdo=0;
//read data in SDI
if(sdi) data_in &=mask; //data_in is already zero, so you only need
//to handle the 1's.
//waiting for rising edge
while((sck==0)&&(cnt<=200)) {
cnt++;
}
mask/=2;
} while(mask); //finishes when eight bits transfered
return data_in;
}
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However the big problem on the read, is that you are doing it a whole clock too late. Think about it. You preload the output value, then wait for a complete clock cycle, and read the input, and load the next output value. One bit late....
If your clock idles 'high', then the version I show will wait for the first falling edge, and then perform both transfers. However this will be the wrong way round if the clock idles low.
Using '/2' on the mask, codes as a rotation _through the carry_. So the bottom bit gets discarded each time, and after the eighth rotation, mask will be zero.
Bit_test, with a variable, is very inefficient. The compiler has to generate a mask, and rotate this the number of bits specified each time. Using your own single mask, just one rotation, for both bits.
Best Wishes |
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