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.C
Joined: 06 May 2004 Posts: 19 Location: Italy
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lcd_putc and printf(lcd_putc,... |
Posted: Tue May 11, 2004 9:04 am |
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Hi,
I'am using this routine to print on the lcd my digits.
Printf(LCD_PUTC...) is more expensive..
void PrintDigit(unsigned int inp)
{
outp[0] = outp[1] = outp[2] = outp[3] = outp[4] = 0;// clear the string
while (inp > 99) {
inp -= 100;
outp[2]++;
}
while (inp > 9) {
inp -= 10;
outp[3]++;
}
outp[4] = inp + 0x30; // add '0' to the results
outp[0] += 0x30;
outp[1] += 0x30;
outp[2] += 0x30;
outp[3] += 0x30;
}
void LCD (int N) {
outp[0] = outp[1] = outp[2] = outp[3] = outp[4] = 0;// clear the string
PrintDigit(N);
if (n>99) { lcd_GOTOXY(9,1); LCD_PUTC(OUTP[2]); }
if (n>9) { lcd_GOTOXY(10,1); LCD_PUTC(OUTP[3]); }
lcd_GOTOXY(11,1); LCD_PUTC(OUTP[4]);
if (n<100) {lcd_GOTOXY(9,1); LCD_PUTC(' '); }
if (n<9) {lcd_GOTOXY(10,1); LCD_PUTC(' '); }
}
/***********/
lcd(200); //example
But I don't know how to print string characters
void Print(int msgIndex) {
int scanMSGLCD;
char const msgLCD[7][17] = { " Hello "," GO ",
" DOWN "," UP ",
etc..
}
IF (MSGINDEX>6) MSGINDEX=0;
lcd_gotoxy(1,2);
for (scanMSGLCD=0;scanMSGLCD<17;scanmsgLCD++) {
>> printf(lcd_putc,"%c",msgLCD[msgIndex][scanmsgLCD]);
}
}
Can you help me to write code for lcd character without printf ?
Thank in advance |
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PCM programmer
Joined: 06 Sep 2003 Posts: 21708
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Posted: Tue May 11, 2004 1:36 pm |
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Quote: | printf(lcd_putc,"%c",msgLCD[msgIndex][scanmsgLCD]);
Can you help me to write code for lcd character without printf ? |
Can't you just do this with a loop ? Read characters from the
string and send them to the lcd driver, one at a time, until you
read an "end of string" character (ie., 0). Then break out of
the loop.
Code: | for(scanMSGLCD=0; scanMSGLCD < 17; scanmsgLCD++)
{
c = msgLCD[msgIndex][scanmsgLCD];
if(c == 0)
break;
else
lcd_putc(c);
} |
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.C
Joined: 06 May 2004 Posts: 19 Location: Italy
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Posted: Wed May 12, 2004 2:40 am |
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yes I think that it is the best way or
do {
ScanMSGLCD++;
c = msgLCD[msgIndex][scanmsgLCD];
lcd_putc(C);
} while (C!=0);
In this case 'Do' is the best
Thanks |
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